Go Math Grade 5 Chapter 4 Test Form B -review
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Chapter four – Parts and Wholes
Page No 50:
Question 1:
Draw a rectangle of length viii cm and width 6 cm. Divide it into 3 equal parts and complete the flag.
The top one – third of our flag is saffron (or orangish). What is the colour of the center one – third of the flag? Where volition yous draw the Ashoka chakra?
How much of the flag will you color greenish?
Answer:
The color of middle one-3rd of the flag is white. The Ashoka chakra is drawn at the centre of the flag. One-third of the flag is coloured greenish.
Question 2:
Now look at this flag. How much of it is black? ________ The green part of the flag tin be written as ________ Is reddish less than one – third of the flag? Why?
Respond:
Full number of parts of the flag = three Now, we see that out of three equal parts, just i office of the flag is black. Thus,
13of the flag is black.
Nosotros can besides run into that out of 3 parts of the flag, only ane role is green. Thus, green office of the flag is
13of the flag.
The red portion of the flag is less than
13of the flag, considering a white emblem is as well nowadays in the crimson portion of the flag.
Question 3:
This is the flag of Myanmar, our neighbour. Is blueish more than than one-quaternary of the flag or less? Approximate how much of the flag is red. Is it more
12? Is it more than three-fourths?
Answer:
The bluish colour is nowadays in less than 1-4th of the flag.
I retrieve, red color is present in more than 3-fourth of the flag.
Page No 52:
Question 1:
Draw a circle of radius 3 cm and cut information technology out. Separate the circumvolve into eight equal parts. Now each function is
18of the circle. Colour
28red,
18orange,
18yellow etc. as shown here. Push a matchstick through the centre of the circle. Your magic top is ready. Spin it fast! What do yous see? Can you see all the colours? Write what you see in your notebook.
Answer:
Disclaimer: Students are advised to set the respond on their own.
Question 2:
Chocolate bar • Manju had a chocolate. She gave one-fourth of it to Raji, 1-third to Sugatha and 1-sixth to Sheela. She ate the remaining part. How many pieces of chocolate did each become?
• What part of the chocolate did Manju swallow?
Answer:
Total number of pieces in the chocolate bar = 12
Manju gives one-4th of the chocolate to Raji. Number of pieces of chocolate given to Raji = 12 ÷ 4 = three
Thus, Raji got 3 pieces of chocolate. Now, Manju gives 1-tertiary of the chocolate to Sugatha. Number of pieces of chocolate given to Sugatha = 12 ÷ 3 = 4
Thus, Sugatha got 4 pieces of chocolate. Now, Manju gives one-sixth of the chocolate to Sheela. Number of pieces of chocolate given to Sheela = 12 ÷ 6 = 2 Thus, Sheela got 2 pieces of chocolate. Full number of pieces of chocolate given to Raji, Sugatha and Sheela = 3 + 4 + two = nine Full number of pieces of chocolate left in the bar = 12 − 9 = iii
As Manju ate the remaining part of the chocolate, she will go 3 pieces of chocolate. Part of the chocolate eaten by Manju =
14
Page No 53:
Question 1:
Color the hats Colour
13of the hats ruby-red. Colour three-fifth hats blue. How many hats did y'all colour red? How many hats did y'all colour blue? What part of the hats are non coloured? 
Respond:
Total number of hats = 15 It is given that we accept to colour
13of hats in carmine. Number of blood-red coloured hats = fifteen ÷ 3 = v = five
It is given that nosotros have to colour
35of the total hats in blue.
One-fifth of the total hats = 15 ÷ v = three Number of blue coloured hats = 3 × 3 = 9
Number of hats that are not coloured = 1 Thus, part of hats that are not coloured =
115
Page No 55:
Question 1:
Greedy Gatekeepers Remember Birbal, the clever minister of King Akbar? (Math-Magic Form 4. page 14) Practise you know how he became a minister? Birbal was then a young boy living in a village. He was very clever and could write poetry. He idea he would effort his luck in the King's courtroom. Then he took some of his poems and set off for the city. When he reached the outer gate of the palace, he was stopped by the gatekeeper. "Hey! Stop in that location! Where are yous going?", shouted the gatekeeper. "I am a poet. I want to come across Male monarch Akbar and show my poems to him", replied the poet. "Oh, you are a poet! The king is kind, he will surely give you a prize. I will let y'all in if you give me
110of your prize".
Immature Birbal agreed since he had no other mode. When he went in, the gatekeeper calculated "If he gets 100 gold coins I will get _________ gold coins". The poet came to a second gatekeeper. This gatekeeper as well said, "I will let you lot in if you lot give me two-fifth of your prize". The poet agreed. The gatekeeper happily calculated, "The poet will get at to the lowest degree 100 gold coins and so I will go ___________ golden coins!" The poet reached the last gate. The gatekeeper said, "I will allow you lot to encounter the rex only if y'all give me half of the prize that you get". The poet had no other way. He agreed and went inside. The gatekeeper thought, "Today is a slap-up day. If he gets 100 gold coins I will become __________ gold coins. But if he gets m coins ― wow! I will get ____________". The male monarch was very happy with the poems and said, "Your work is very skilful. You tin ask anything as your prize". "My Lord, I want 100 slaps". "What! 100 slaps? ___________". The male monarch was shocked ― • What happened subsequently that? Consummate the story. What part of the prize did the poet get?
Respond:
The first gatekeeper thought that the king would requite 100 gilt coins to Birbal as a prize. The first gatekeeper demanded
110 of the prize that he would go from the king. So, number of gold coins that would be received by first gatekeeper = 100 ÷ 10 = ten
The second gatekeeper demanded
25 of the prize that Birbal would receive from the king. One-fifth of 100 = 100 ÷ 5 = 20
So, number of gilded coins that would be received by second gatekeeper = twenty × 2 = forty
The third gatekeeper demanded half of the prize that Birbal would receive from the king. Then, number of gold coins that would be received by 3rd gatekeeper = 100 ÷ 2 = fifty
After listening to his poems, the king became happy. Then, Birbal requested the king to requite him 100 slaps as a prize.
Hence, the third gatekeeper got l slaps, 2d gatekeeper got 40 slaps, and the first gatekeeper got ten slaps. The poet got 0 slaps.
Page No 57:
Question ane:
Make different patterns by colouring some squares in the grids B, C, D. What part of the grid did you lot colour? What part of the filigree remained white? Write.
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.png)
.png)
.png)
Answer:
.png)
.png)
.png)
Question two:
Look at filigree A once again. Is the filigree coloured ̢ۥ (a)
12 blue, 12 white?(b)
24 blueish, 24 white?(c)
38 blueish, 58 white?(d)
48 bluish, 48 white?Mark (✕) on the incorrect respond.
Answer:
Full number of squares in grid A = xvi Number of squares that are blueish-coloured = 8 Number of squares that are white-coloured = eight
Fraction of filigree A that is blue-coloured =
12Fraction of filigree A that is white-coloured =
12So,
12of the filigree A is blue and
12of the filigree A is white.
12=24=48
| a) 12blue, 12white | b) 24blue, 24white |
| c) 38blue, 58white (×) | d) 48blue, 48white |
Question 3:
Draw grids of sixteen squares and brand patterns with (a)
28 ruby-red, 12 yellow, 14 dark-green(b)
316 blue, 516 red, 12 yellow
Reply:
(a)
.png)
(b)
.png)
Page No 58:
Question 1:
Ramu's vegetable field has 9 equal parts. What vegetables does he grow?
(i) Which vegetable grows in the biggest part of his field? What part? (2) On what function of the field does he abound potatoes? (3) What part of the field is used to grow spinach? What function is used for brinjals? (iv) Now you write some questions past looking at this picture.
Answer:
Ramu grows capsicum, brinjal, tomatoes, spinach and potatoes in his field.
1) Total number of parts of the vegetable field= 9 Ramu grows tomatoes in the biggest role of his field. Part of field used for growing tomatoes = 3 Function of field used for growing tomatoes =
39 =
thirteen Ramu grows tomatoes in one-3rd of the field.
ii) Office of field used for growing potatoes = 2 Total number of parts of the vegetable field = 9 Office of the field used for growing potatoes =
29 And then, Ramu grows potatoes in two-ninth function of the field.
3) Total number of parts of the vegetable field = 9 Number of parts used for growing spinach = 1 So, role of the field used for growing spinach =
19 Number of parts of field used for growing brinjals = 2 So, part of the field used for growing brinjals =
29 Thus, Ramu grows spinach and brinjals in one-9th and two-9th part of the field respectively.
4) (1) Which vegetables are grown in the least part of the field? (2) What is the function of the field used to abound raddish and tomatoes together? Disclaimer: The answer to role (iv) of the question may vary from educatee to student. Information technology is highly recommended that the students prepare the answer on their own. The answer provided here is for reference only.
Page No 59:
Question 1:
Ramu wanted to give beneath vegetables to his friends. He gave Aboobacker one-fifth of these tomatoes and
13of the potatoes. Srija got
25of the tomatoes and
36of the potatoes. Nancy got the residuum of these vegetables. Circle Aboobacker'south share in blue. Circle Srija's share in yellow.
• How many potatoes and tomatoes did Nancy become?
Respond:
Total number of tomatoes = 20 Total number of potatoes = 18
Aboobacker got one-5th of the tomatoes, and one-third of the potatoes.
Number of tomatoes with Aboobacker = 20 ÷ 5 = 4 Number of potatoes with Aboobacker = 18 ÷ iii = half-dozen
And so, we will circle 4 tomatoes and 6 potatoes in blueish to show Aboobacker's share. Srija got ii-fifth of the tomatoes and three-6th of the potatoes. Number of tomatoes with Srija = 2 × 4 = 8 Ane-6th of 18 = iii Number of potatoes with Srija = 3 × 3 = 9
.png)
Thus, Ramu gave 4 tomatoes to Aboobacker and 8 tomatoes to Srija. And so, he gave a full of 12 tomatoes to Aboobacker and Srija.
Now, Ramu gave 6 potatoes to Aboobacker and 9 potatoes to Srija. So, he gave a full of xv potatoes to Aboobacker and Srija.
Number of tomatoes left = 20 − 12 = eight Number of potatoes left = 18 − 15 = three
Thus, Nancy got eight tomatoes and 3 potatoes.
Page No 60:
Question i:
The Menu Puzzle
(1) Separate the white surface area in square A into ii equal parts. Got the answer? Was that easy? At present exercise the 2d question. (ii) Divide the white expanse in square B into three equal parts! That too is easy, isn't it? At present see the third question. (iii) Split the white surface area in square C into 4 equal parts!! Is it a chip hard? Don't worry, have your fourth dimension. Just if y'all have given up, expect for the respond. Hither comes the last question. (4) Divide the white expanse in square D into seven equal parts!!!! The earth record for this is 7 seconds. But yous can take minutes! Tired of thinking? Look for the answer on page 68. Then was that difficult??
Page No 61:
Question 1:
What part of each shape is coloured? First approximate the answer, and so bank check.
(one) .png)
(two)
.png)
(3)
.png)
(4)
.png)
Reply:
Following are the guesses : 1) One-eighth of the shape is coloured. two) One-sixth of the shape is coloured. iii) Ii-ninth of the shape is coloured. four) 4-fifteenth of the shape is coloured.
To cross-bank check our estimate, we will divide each of the given shapes into equal parts of size of the coloured part as shown below :
(1) .png)
(two) (1).png)
(iii) (2).png)
(iv) .png)
On cross-checking, nosotros at present observe that our guess is right.
Page No 62:
Question 1:
Look at the small triangle. What part of the foursquare is it? How will you find this out?
Respond:
We will divide the whole foursquare into small triangles as shown in the adjoining figure.
.png)
We will get 16 such triangles.
Total number of triangles = 16 Number of coloured triangles = one Fraction of square coloured =
116Thus, the coloured pocket-sized triangle is one-sixteenth of the square.
Question 2:
Coloured Parts Complete these (i)
(1).png)
This circle is divided into ii equal parts. Out of _________ equal parts 1 office is coloured bluish.
(2)
.png)
Here the circle is divided into _________ equal parts. Out of ________ equal parts, ________ parts are coloured blue.
(iii)
.png)
Here the circle is ………………………………………
(4)
.png)
Here the circumvolve is ………………………………………
Answer:
(1) The circumvolve is divided into 2 equal parts. Out of 2 equal parts, one part is blue in colour.
(two) Here, the circle is divided into four equal parts. Out of 4 equal parts, two parts are bluish-coloured.
(three) Here, the circle is divided into six equal parts. Out of 6 equal parts, three parts are blue-coloured.
(4) Hither, the circle is divided into viii equal parts. Out of eight equal parts, four parts are bluish-coloured.
So, we tin say that,
12 = 24 = 36 = 48
Page No 63:
Question 1:
Ramesh bought a piece of halwa for his children Ammu and Anu. He divided it every bit for them. • Each will go __________ part of halwa. "This piece is too big. We tin can't eat it", they said. So he divided the pieces into half over again. Now how many pieces volition Ammu become? ________ • What function of the halwa is it? _________ "Go far even smaller, Dad" they asked. So he once again cut the halwa into smaller pieces. "Ok, thank y'all, Dad." • At present how many pieces volition each become? • What function of the halwa is each piece now? • If Ramesh had cut the halwa into vi equal parts how many pieces would each take got? Look at your answers for questions 1 to 4 and write ―
12= ̢ۥ = ̢ۥ = ̢ۥ = ̢ۥ = ̢ۥ
Reply:
• When Ramesh divides the piece of halwa in two parts,and so each kid will become one-half part of halwa. Each volition go
12part of halwa.
• When each of the two pieces of halwa is divided into 2 equal parts, and then in that location volition exist a full of 4 pieces of halwa. Now, each of the child gets ii pieces of halwa.
Thus, Ammu will become 2 pieces of halwa.
Total number of pieces of halwa = four Number of pieces with Ammu = ii Part of halwa that Ammu gets =
24=
12Thus, Ammu will get one-half office of the halwa.
• When each of the 4 pieces cutting over again into halves, and then we have a total of 8 pieces of halwa. At present, each kid will get iv pieces of halwa.
• Equally i whole piece of halwa is now divided into viii equal halves, each piece is
18part of the whole piece.
• When Ramesh divides the halwa into half dozen equal parts, and then each of the two child gets 3 pieces of halwa.
12 = 24 = 36 = 48 = 510 = 612
Page No 64:
Question i:
Look at the picture. Write what part of the strip is each green slice. Write the part for a piece of each color.
How many one-fourths will brand a half? How many
18will make
14? How many
18are in
12? Now inquire your friends some questions on the same motion-picture show.
Answer:
The green strip is divided into 4 equal parts. Thus, each part is
14of the whole light-green strip.
Two one-fourths will make a half.
14 + 14 = i + 14 = 24 = 12Two one-eighths will make
14.
xviii + 18 = 1 + eighteen = 28 = 14 Disclaimer: The questions to be asked to friends may vary from student to student. It is highly recommended that the students prepare the respond on their ain. The answer provided here is for reference only.
Question 2:
Patterns Wait at this square. What role is coloured blue? What part is light-green?
Answer:
We volition draw a filigree to find the portion of each colour in the following square.
Total number of small squares in the grid = sixteen Number of pocket-sized blue coloured squares = ii Fraction of blue shaded square =
216 =
18Thus, one-eighth of the square is shaded blue.
Number of light-green shaded squares = ane Fraction of green shaded square =
116Thus, one-sixteenth of the square is shaded green.
Question three:
Ammini says one-half of half and ane-third of three-quarters are equal. Do you lot concur? How will you show this?
Answer:
We tin can bear witness the above with the help of figures.
.png)
.png)
One-half Half of half
.png)
.png)
iii quarters ane third of 3 quarters
So, half of half is equal to one-quarter, and i-third of three-quarters is equal to one-quarter. Thus, we can say that half of half is equal to one-3rd of three quarters.
Page No 65:
Question 1:
This testify
15petals of a flower. Complete the flower by cartoon the other petals.
Reply:
Question two:
The flick shows 1-third of the blades of a fan. Complete the picture by cartoon the other blades. .png)
Answer:
Question 3:
Half of the blades of some other fan are shown here. Complete the motion-picture show by cartoon the other half. How many blades take you lot drawn?
.png)
Reply:
We take drawn two more blades to complete the moving picture.
Question 4:
How many.png)
will make one rupee? Is fifty paise half of ane rupee? How many .png)
will make one rupee?
25 paise is _________ office of one rupee 20 paise is _________ part of one rupee How many x paise will make one rupee? So 10 paise is ________ part of ane rupee.
Answer:
We know that,
Ane rupee = 100 paise Number of 50 paise coins in ane rupee = 100 ÷ fifty = 2
So, two 50 paise money volition make one rupee.
At that place are 2 fifty paise coin in one rupee. So, 50 paise is half of one rupee.
We know that, 100 paise = Re 1 Number of 25 paise in one rupee = 100 ÷ 25 = 4 So, four 25 paise coins volition make 1 rupee.
Nosotros know that, 4 25 paise coins volition make 1 rupee. So,25 paise is one-fourth part of one rupee.
Number of 20 paise money in one rupee = 100 ÷ 20 = 5
There are five 20 paise money in one rupee. Then, 20 paise is ane-5th function of one rupee.
Number of 10 paise coin in one rupee = 100 ÷ 10 = 10 X 10 paise money will make one rupee.
So x paise is one-tenth role of one rupee.
Page No 66:
Question ane:
An Old Woman's Will Once there lived an old woman. She lived with her three daughters. She was quite rich and had xix camels. One day she fell sick. The daughters called the doc. The doctor tried his best but could non salvage the woman. Afterward her death, the daughters read what she had written in her will.
12of my camels My second girl will get
14of my camels My third daughter will get
15of my camels
The daughters were really puzzled. "How can I get
12of the 19 camels?" asked the eldest daughter. "Half of 19 is nine and a half. But nosotros can't cut the camel!" The 2nd daughter said. "That is right. But what will nosotros exercise at present?" asked the third daughter". Simply then they saw their aunt coming. The daughters told her their problem. "Show me the will. I have an idea. You take my camel. And so you take 20 camels. Now tin you carve up them as your mother wanted?" the aunt said. "You lot desire one-half of the camels, don't you lot? Accept 10 camels" she said to the eldest daughter. "Take your share", the aunt told the 2nd daughter. She took one-quaternary of the camels and got _________ camels. "Yous can take one-fifth of the camels", the aunt told the third daughter. She got ________ camels. The daughters were very happy and counted their camels 10+____+____=19. "The i remaining is mine", said the aunt and took her camel away!
• How did this happen? Discuss.
Answer:
Total number of camels = 20 Number of camels given to starting time daughter = 20 ÷ 2 = x Thus, beginning daughter got 10 camels in her share.
Number of camels given to 2d girl = 20 ÷ iv = v Thus, second daughter got 5 camels in her share.
Number of camels given to tertiary daughter = 20 ÷ five = 4 Thus, third daughter got four camels in her share.
ten + 5 + 4 = xix When the daughters counted their camels, they found that there were in total 19 camels to be divided among them in total.
The division of 19 camels among three daughters in the given fractions was possible only when the aunt included her camel.
Page No 67:
Question 1:
Arun's Time Table .png)
Sleeping: Ane 3rd of a day Utilize different colours to bear witness Playing: One eight of a day Studying:
14of a day How many hours does Arun take for
Sleeping?%20(1)(1).png)
hours
Studying?(1).png)
hours
Playing?.png)
hours What part of the day does he use for other activities?
Reply:
.png)
Total number of hours in ane day = 24 Arun sleeps i-tertiary of a day. Number of hours that Arun sleeps = 24
÷3 = 8
Thus, Arun sleeps for 8 hours in a day. Arun plays for ane-8th of a day. Number of hours Arun takes to play = 24
÷viii = iii Arun studies one-fourth of a twenty-four hours. Number of hours Arun takes to report = 24
÷4 = 6
Total number of hours spent in studying, playing and sleeping = vi + 3 + 8 = 17 Number of hours left for other activities = 24 − 17 = seven And then, part of the solar day used for other activities =
724Thus, Arun uses vii twenty-fourth of the day for other activities.
Folio No 68:
Question 1:
A school has decided to bring out a mag every quarter of the year. How many magazines will they have in a year? If they want to print it at the cease of each quarter of a year, which are the months for printing? Mark the number for those months.
| 1 | 2 | 3 | four | five | 6 | 7 | 8 | 9 | ten | 11 | 12 |
Answer:
Nosotros know that,
one year = 12 months Quarter of an twelvemonth = 3 months Number of quarters in 1 year = 12 ÷ 3 = iv
A schoolhouse brings 1 mag every quarter of the twelvemonth. Number of magazines brought by school in 1 year = i × iv = 4
As the magazines are printed at the end of each quarter of the yr, March, June, September and December volition exist the months for printing.
The given months are marked on the strip equally :
Question 2:
Have you lot heard of Kumbhakarna, the brother of Ravana? He is famous for sleeping for one-half a twelvemonth. Most people slumber about eight hours a day. Then what part of a day is it? _________
And so what office of a year do they sleep? A person 60 years old must accept slept ________ years!!!
Respond:
Full number of hours in one day = 24 Number of hours people slept = 8 Role of the solar day people slept =
824 =
13It is one-tertiary part of a solar day.
Number of days in 1 ordinary yr = 365 Number of hours in one day = 24 Number of hours in 365 days = 365 × 24 = 8760
Number of hours that people slept in one 24-hour interval = 8 Number of hours that people slept in 365 days = 365 × 8 = 2920
The part of the yr that people slept =
29208760 =
13So, people slept 1-third of the year.
A man sleeps one-third part of an twelvemonth. Number of years a man of threescore years slept = sixty ÷ 3 = xx
Thus, a human being of threescore years must have slept xx years.
Page No 69:
Question one:
Look at the yellow price list. (a) How much does two kg of tomato toll? (b) How much does
12kg of tomato cost? (c) Kiran wants
212kg of tomato. How much will it cost? (d) How much does
312kg potato price? (e) What is the price of
114kg of carrot? (f) He bought a gourd of weight
434kg and it costs _________ (g) Look at the shopping list in Keerti's hand. How much will she take to pay to buy all of these?
.png)
(h) Brand a bill of your own for vegetables you lot want to buy. Find the total coin you will accept to pay.
| Item | Price in Rs (per kg) | Amount |
| Total | ||
Respond:
a) Cost of 1 kg tomato = Rs 12 Cost of ii kg tomatoes = Rs 2 × 12 = Rs 24
b) Toll of 1 kg tomato = Rs 12 Price of
12kg tomatoes = Rs 12 ÷ 2 = Rs six
c) Toll of one kg tomato = Rs 12 So, price of
212kg tomatoes = Rs 12 + Rs 12 +Rs 6 = Rs 30
d) Cost of 1 kg potato = Rs 10 Toll of
12kg potato = Rs 10 ÷ ii = Rs 5
Cost of
212kg white potato = Rs 10 + Rs 10 + Rs v = Rs 25
east) Cost of i kg carrot = Rs 18 Cost of
14kg carrot = Rs 18 ÷ iv = Rs
184 Cost of
114kg carrot = Rs xviii + Rs
184 = Rs
2212f) Price of 1 kg gourd = Rs 8 Cost of
34kg gourd = Rs 6
Cost of
434kg gourd = Rs viii × 4 + Rs vi = Rs 32 + Rs 6 = Rs 38
yard) Price of 1 kg murphy = Rs 10 Cost of
14kg potato = Rs 10 ÷ 4 = Rs
104Cost of
214kg potato = Rs ten × 2 + Rs
104 = Rs
94 × 10 = Rs
452 = Rs
2212h)
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Page No seventy:
Question ane:
Raheem'southward journey Raheem has to travel
114km to reach schoolhouse. What distance does he travel to get to school and come back home?
Respond:
Distance travelled by Raheem to reach school from home =
114km
Distance travelled by Raheem to return home from school =
114km
Total distance travelled by Raheem =
114 + 114
= 1 + one + 14 + 14= 2 + 24= two + 12= 212 km Thus, the full altitude travelled past Raheem to go and render from schoolhouse is
212km.
Question 2:
What coins? Latha bought a pencil and a pen for seven and a half rupees. She gave Rs 10/−. The shopkeeper gave back the money in half and quarter rupees. What are the coins she got?
Answer:
Toll of a pen and a pencil = Rs
712Total coin given to the shopkeeper = Rs ten
Total money returned to Latha by the shopkeeper = Rs 10 − Rs
712
=10-seven-12=3-12=Rs 212 Nosotros know that, 1 quarter rupee = 25 paise 1 half rupee = fifty paise
Now, the shopkeeper can return Rs
212in the following ways : a) one one-half rupee coin and viii quarter rupee coins
b) 4 half rupee coins and 2 quarter rupee coins
c) two half rupee coins and 6 quarter rupee coins
d) iii half rupee coins and 4 quarter rupee coins
Question 3:
At the railway station .png)
.png)
(a) What time is the train expected to come up today? (b) Nazia gets off at a station later
212hours from this station. What time volition she go off? (c) Shaji will have 5 hours to attain Ernakulam by this train. At what time volition he attain there?
Answer:
a) The correct time for the arrival of the train is quarter to seven
=
634hrs
Merely, the train is late past half an hour.
Then, expected time of the arrival of the railroad train =
634 + 12 =
274 + 12 =
274 + 1 × 22 × 2 =
274 + 24 =
294 =
714 Thus, the expected time of the arrival of the train is quarter past seven.
b) Expected time of the inflow of the railroad train =
714hrs
Nazia gets off at a station after
212hrs of boarding the train.
Time at which Nazia volition become off =
714 + 212 =
294 + 52 =
294 + 5 × 22 × 2 =
294 + 104 =
29 + 104 =
394 =
934 Thus, Nazia volition get off from the train at quarter to 10.
c) Shaji will accomplish Ernakulam past this train after 5 hours.
Expected fourth dimension of the arrival of the train =
714hrs
Expected fourth dimension at which Shazi will reach Ernakulam =
714 + 5 =
294 + 51 =
294 + five × 41 × iv =
294 + 204 =
29 + 204 =
494 =
1214Thus, Shazi will accomplish Ernakulam at quarter past 12.
Source: https://www.freencertsolutions.com/ncert-solutions-for-class-5-math-chapter-4-parts-and-wholes/
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